Math, asked by princy1418, 10 months ago

Factories the following expression
3. y²+у - 132=​

Answers

Answered by p7604975
4

Answer:

y²+y-132=0

ݲ+12y-11y-132=0

y(y+12)-11(y+12)=0

y=11 or y=-12

Answered by Anonymous
2

Answer:

(y+12)(y-11)

Step-by-step explanation:

y^{2} + y -  132

= y^{2} + 12y - 11y - 132

= y(y + 12) - 11(y +12)

= (y+12)(y-11)

Hope it helps!

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