Question

factories the following : x²+9x+20 ​

Answer 1

${x}^{2} + 9x + 20 \\ = {x}^{2} + 5x + 4x + 20 \\ = x(x + 5) + 4(x + 5) \\ = (x + 5)(x + 4)$

Answer 2

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factories the following : x²+9x+20 .

$\huge\red{\mid{\underline{\overline{\textbf{Solution\:࿐}}}\mid}}$

$x {}^{2} + 9x + 20$

by making suitable factors of 20' we get =2×2×5

.'. 4+5=9 . here 9 is the middle term , which we have to make.

so'!

$x {}^{2} + 4x + 5x + 20$

by Taking common'~

$x(x + 5) + 4(x + 5)$

$(x + 4)(x + 5) = 0$

.'.

$x + 4 = 0 \: \: \: \: and \: x + 5 = 0$

keeping both the tems equal to zero.

we get :

$x = - 4 \: \: and \: x = - 5$

$\sf\red{hope\:it\:helps\:you}$