Question

factories the following y^3+y^2-y-1 3 factors
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Answer 1

Answer:

(y−1)(y+1) =2

Step-by-step explanation:

The value of y 3+y 2 −y−1 isy 3 −y 2 +2y 2−2y+y−1=y 2 (y−1)+2y(y−1)+1(y−1)=(y−1)(y 2 +2y+1)=(y−1)[y 2 +y+y+1]=(y−1)[y(y+1)+1(y+1)]=(y−1)(y+1)=2

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