Question

factories the given Q:-<br />x³-23x²+142x-120

Answer 1

substitute 1 in the equation u will get zero there 1 is one of the root.
next part u can solve by two methods synthetic division or by normal one
I'm using here synthetic
1( 1 -23 142 -120)
0 1 -22 120
1 -22 120 0
there the equation we got
(x²-22x+120)(x-1)=0
solve this
x²-12x-10x+120=0
(x-12)(x-10) =0
there fore x = 10,12,1