Question

factories this number x³+3x²+3x+1

Answer 1

The identity
$( {x + y)}^{3} = ( {x}^{3} + 3 {x}^{2} y + 3x {y}^{2} + {y}^{3} ) \\ compare \: the \: eq \: with \: this \: identity \\ ( {x + 1)}^{3} = ( {x}^{3} + 3 {x}^{2} (1) + 3x {(1)}^{2} + {(1)}^{3} \\ = {x}^{3} + 3 {x}^{2} + 3x + 1)$
so factors are
$( {x + 1)}^{3} \\ or \: \: (x + 1)(x + 1)(x + 1)$