Math, asked by hellousha10, 6 months ago

factories using identity 16a²b - 64b³​

Answers

Answered by engineerfarhan1122
1

Answer:

16b(a+2b)(a-2b)

Step-by-step explanation:

take 16 common

16(a^2b-4b^3)

take b common

16b( a^2-4b^2)

16b(a+2b)(a-2b)

answer

Answered by Anonymous
1

16a²b-64b³

=16b(a²-4b²)

= 16b{(a)²-(2b)²}

Using identity a²-b² = (a-b)(a+b)

= 16b{(a+2b)(a-2b)}

= 16(a+2b)(a-2b)

Hope it helps.....

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