Question

factories (x+2) (x+3) (x-7) (x-2) + 64​

Answer 1

Answer:

(x+2)(x+3)(x-7)(x-2)+64.

(x+2)(x+3).

It is in the form of (x+a)(x+b)=x²+(a+b)x+ab where x=x, a=2 & b=3.

(x+2)(x+3)=x²+(2+3)x+(2)(3).

=x²+5x+6.

(x-7)(x-2).

It is in the form of (x-a)(x-b)=x²-(a-b)x-ab where x=x, a=-7 & b=-2.

(x-7)(x-2)=x²-(-7-(-2))x-(-7)(-2).

=x²-(-7+2)x-(14). (Because -×-=+).

=x²-(-5)x-14. (Because -×+=- & largest number is important).

=x²+5x-14. (Because -×-=+).

(x+2)(x+3)(x-7)(x-2)+64=(x²+5x+6)(x²+5x-14)+64. (Because (x+2)(x+3)=x²+5x+6 & (x-7)(x-2)=x²+5x-14).

=x⁴+25x²-84+64. (Because x²×x²=x⁴, x×x=x² & +×-=-).

=x⁴+25x²-20. (Because -×+=- & largest number is important).

I think this is your answer.