factories x^3+4x^2+4x+3
Answers
Answer:
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
0-(x^3-4*x^2-4*x-3)=0
0 - ((((x3) - 22x2) - 4x) - 3) = 0
x³+4x²+4x+3 is not a perfect cube.
Solution:
Thoughtfully split the expression at hand into groups, each group having two terms :
Group 1: -x³+3
Group 2: 4x²+4x
Pull out from each group separately :
- Group 1: (-x³+3) • (1) = (x³-3) • (-1)
- Group 2: (x+1) • (4x)
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Find roots (zeroes) of : F(x) = -x3+4x2+4x+3
Polynomial Roots Calculator is a set of methods aimed at finding values of x for which F(x)=0.
Let us test ....
P Q P/Q F(P/Q) Divisor
-1 1 -1.00 4.00
-3 1 -3.00 54.00
1 1 1.00 10.00
3 1 3.00 24.00
Hope it will be helpful :)
Step-by-step explanation:
check out the above photograph.
Hope it helps you. If any doubt then please comment.
