Question

factories x^3+4x^2+4x+3​

Answer 1

Answer:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

0-(x^3-4*x^2-4*x-3)=0

0 - ((((x3) - 22x2) - 4x) - 3) = 0

x³+4x²+4x+3 is not a perfect cube.

Solution:

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1: -x³+3

Group 2: 4x²+4x

Pull out from each group separately :

• Group 1: (-x³+3) • (1) = (x³-3) • (-1)
• Group 2: (x+1) • (4x)

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Find roots (zeroes) of : F(x) = -x3+4x2+4x+3

Polynomial Roots Calculator is a set of methods aimed at finding values of x for which F(x)=0.

Let us test ....

P Q P/Q F(P/Q) Divisor

-1 1 -1.00 4.00

-3 1 -3.00 54.00

1 1 1.00 10.00

3 1 3.00 24.00

Hope it will be helpful :)

Answer 2

Step-by-step explanation:

check out the above photograph.

Hope it helps you. If any doubt then please comment.