Question

factories x^6 - 64 ..please answer my question

Answer 1

Hey there!

This is surely a good question and needs some good Brainly content rich answer!

So, We are asked to factorise x^6 - 64 , So we will be using some algebraic identities.


${x}^{6} - 64 \\ = {x}^{6} - {2}^{6 } \\ = {( {x}^{3}) }^{2} - { ({2}^{3}) }^{2} \\ = ( {x}^{3} + {2}^{3} )( {x}^{3} - {2}^{3} )$

= (x + 2 ) (x² - (x)(2) + 2²) ( x - 2 )( x² + 2x + 4 )

= ( x + 2 ) ( x - 2 )( x² - 2x + 4 )( x² + 2x + 4 )

The formulae or formulas which were used

a² - b² = ( a + b) ( a - b)
a³ - b³ = ( a - b) ( a² + ab + b² )
a³ + b³ = ( a + b) (a² - ab + b² )

Hope you are helped!

Answer 2

Step-by-step explanation:

1. x^3+y^3=(x-y)(x^2-xy+y^2)
2. x^3-y^3=(x+y)(x^2-xy+y^2)