factories x cube + 6x square +11x + 6
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Answer.
- Factorised form – (x + 1)(x + 2)(x + 3)
Steps.
Given:
→ f(x) = x³ + 6x² + 11x + 6
Put x = -1, we get,
→ f(-1) = (-1)³ + 6 × (-1)² + 11 × (-1) + 6
= -1 + 6 - 11 + 6
= 12 - 12
= 0
So, by factor theorem,
→ (x + 1) is a factor of f(x).
Divide f(x) by (x + 1):
x + 1 ) x³ + 6x² + 11x + 6 ( x² + 5x + 6
x³ + x²
–––––––––––––––––––––
5x² + 11x + 6
5x² + 5x
–––––––––––––––––––––
6x + 6
6x + 6
–––––––––––––––––––––
0
Therefore:
→ f(x) = (x + 1)(x² + 5x + 6)
= (x + 1){x² + 2x + 3x + 6}
= (x + 1){x(x + 2) + 3(x + 2)}
= (x + 1)(x + 2)(x + 3)
Which is our required answer.
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