Question

Factories÷
x²-2x-2x=0
please write correct answer and full step please​

Answer 1

$x²-2x-2x=0$

$x²-4x=0$

$x = \frac{ - b \underline + \sqrt{ {b}^{2} } - 4ac}{2a}$

a=1

b=-4

c=0

$x = \frac{ - ( - 4) \underline + \sqrt{ {( - 4)}^{2} } - 4 \times 1 \times 0}{2 \times 1}$

$x = \frac{4 \underline + 4}{2}$

$x = \frac{4 + 4}{2}$

$x = \frac{4 - 4}{2}$

x=4

x=0

Answer 2

Answer:

$x^2-2x-2x=0\quad :\quad x=4,\:x=0$

Step-by-step explanation:

$\mathrm{Refine}$

$x^2-4x=0$

$x_{1,\:2}=\frac{-\left(-4\right)\pm \sqrt{\left(-4\right)^2-4\cdot \:1\cdot \:0}}{2\cdot \:1}$

$\sqrt{(-4)^2 - 4 * 1-0 = 4}$

$x_{1,\:2}=\frac{-\left(-4\right)\pm \:4}{2\cdot \:1}$

$\mathrm{Separate\:the\:solutions}$

$x_1=\frac{-\left(-4\right)+4}{2\cdot \:1},\:x_2=\frac{-\left(-4\right)-4}{2\cdot \:1}$

$\frac{-\left(-4\right)+4}{2\cdot \:1}$

Apply rule = - (-a) = a

$=\frac{4+4}{2\cdot \:1}$

$\mathrm{Add\:the\:numbers:}\:4+4=8$

$=\frac{8}{2\cdot \:1}$

$\mathrm{Multiply\:the\:numbers:}\:2\cdot \:1=2$

$=\frac{8}{2}$

$\mathrm{Divide\:the\:numbers:}\:\frac{8}{2}=4$

$\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}$

$x=4,\:x=0$