Math, asked by rajshreebaid59, 1 day ago

factories X2 - 2xy - 3y2​

Answers

Answered by kts182007
0

Answer:

(x + y)(x - 3y)

Step-by-step explanation:

We can use trinomial factorisation to split the middle term

Product = -3x²y²

Sum = 2xy

x² - 2x - 3y²

= x² - 3xy + xy - 3y²

= x(x - 3y) + y(x - 3y)

= (x + y)(x - 3y)

Answered by yassersayeed
0

In the above question given data

we have factorize the above equation

we are solving in the following way consider

the given expression

The equation isX^{2} -2xy-3y^{2}

X^{2} -2x-3y^{2} \\X^{2} -3xy+xy-3y^{2} \\X(x-3)+y(x-3y)\\(x+y)(x-3y)

Hence the required factorization is

(x+y)(x-3y)

Note;the given equation should be

X^{2}-2xy-3y^{2}

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