Question

factories:- x² -3√5x-20​

Answer 1

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x2 + x - 20 = 0

[by factorisation method]

⇒ x2 + 5x - 4x - 20 = 0

⇒ x(x + 5) - 4(x + 5) = 0

(x + 5) (x - 4) = 0

∴ x = -5 or 4

and y2 - y - 30 = 0

⇒ y2 - 6y + 5y - 30 = 0

⇒ y(y - 6) + 5(y - 6) = 0

⇒ (y - 6) (y + 5) = 0

∴ y = 6 or - 5

Hence, y ≥ x or x ≤ y