Question

factories x²-42x+440​

Answer 1

Given: The equation is$x^{2} -42x+440$.

We have to factorize the above equation.

We are solving in the following way:

We have,

The equation is$x^{2} -42x+440$

$=>x^{2} -20x-22x+440\\=>x(x-20)-22(x-20)\\=>(x-20)(x-22)$

The factors are$(x-20)(x-22)$.

$=>(x-20)(x-22)\\=>x-20=0;x-22=0\\=>x=20;x=22$

Hence, the factors are$(x-20)(x-22)$ and roots are$20or22$.