Question

factories X²- 7x - 19​

Answer 1

$\huge\tt{\bold{\underline{\underline{Answer᎓}}}}$

Step by step explanation:

${x}^{2} - 7x - 19 = 0$

Here,it is in the form of a quadratic equation .

Here,a=1;b=-7. &c=-19

Here ,we use quadratic formula for finding roots:

$x = \frac{ -b ± \sqrt{ {b}^{2} - 4ac } }{2a}$

$= > x = \frac{ - ( - 7)± \sqrt{ {( - 7)}^{2} - 4(1)(19)} }{2}$

$= >x = \frac{7± \sqrt{49 - 76} }{2}$

$= > x = \frac{7± \sqrt{ - 27} }{2}$

$\bold{= > x = \frac{7±3 \sqrt{3i} }{2}}$

Here,iota(i) is used inside root because there is negative value -27 inside root and iota is used in place of negative root value.

Answer 2

Step-by-step explanation:

given=$x^{x} -7x-19$

solution

The first term is, $x^{x}$  its coefficient is  1 .

The middle term is,  $-7x$  its coefficient is  -7 .

The last term, "the constant", is  -19

Step-1 : Multiply the coefficient of the first term by the constant  $1*-19=-19$

Step-2 : Find two factors of  -19  whose sum equals the coefficient of the middle term, which is   -7 .

$-19 + 1 = -18 \\ -1 + 19 = 18$

No two such factors can be found .