Question

factories x³-23x²+142x-120

Answer 1

x^3-23x^2+142x-120
x^3-12x^2-11x^2+132x+10x-120
x^2(x-12)-11x(x-12)+10(x-12)
(x-12)(x^2-11x+10)
(x-12)(x^2-10x-x+10)
(x-12){x(x-10)-1(x-10)}
(x-12)(x-1)(x-10)

Answer 2

Here is your answer dude

x^3 - 23x^2 +142 x -120
=>
Put the value of 1 in equation

( 1)^3 -23×1^2 +142×1 -120

1 -23 +142-120

=> 142 -142

=> 0

=============================
x^2 ( x-1) -22x (x-1) +120 (x-1)

Then

(x-1) (x^2- 22x +120)

Now factories the equation
(x^2 -12x -10x +120)

{ X (x-12) -10 (x-12) }

Then

(x-1) (x-12) (x-10) answer

Hope it's helpful!!
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