Question

factories x3+3x2+3x-7

Answer 1

Hy friend, there. Might be some problem in ur question...
If the digits u hv written after numbers are powers....
So here's ur ans....
x³+3x²+3x-7

= x³ + 3x² + 3x +1 -8

= (x + 1)³ -(2)³

Now, use identity

a³ - b³ = (a-b) ( a² + ab + b²)

We get, ( x+1 -2) { (x+1)² + 2(x+1) + 2² }

= (x-1) ( x² + 2x + 1 +2x + 2 + 4)

= (x-1) ( x² + 4x + 7)

Hope it helped u...

Answer 2

Hey user !!

Here is your answer !!

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Given ->

↪x^3 + 3x^2 + 3x - 7 = 0

Solution ->

↪Firstly we will use polynomial division method here.

↪Divide (x+1) with given polynomial.

↪When you will divide u will get the factors

↪( x + 1 ) ( x^2 - 4x - 7 )

Hope it is satisfactory :-)

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