factories :X3-8x2+X+42
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Step-by-step explanation:
Secondary SchoolMath 5+3 pts
Factorize x^3 - 8x^2 + x + 42
Report by Amiyasingh 23.05.2018
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Arvinddashora · Helping Hand
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kaushikvidit007
Kaushikvidit007 Expert
ok ..the first thing u do in ques in which u have x to the power 3 is
step 1 : try to put in some no. like ( -1 ,1 ,0 ,2,-2,-3 ... etc ) so that the equation becomes = 0 , in this que , if u try to put +3 u will see u get zero it becomes
27 - 8(9) +3 +42 = 72 -72 =0
so ur first factor is 3 hence u write it as (x-3)
step 2 : now take the coefficients of the equation ie 1 -8 1 42 factorise it with 3 like this
3( 1 -8 1 42 )
____3_ -15_-42_
1 -5 -14 0
step 3 : take des coefficients 1 ,-5 ,-14 , write the equation as x^2 -5x -14 then factorise it ... u will get the factors (x-7)(x+2)
hence the final answer will be
x^3 - 8x^2 + x +42 = (x-3)(x-7)(x+2)
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Answer:
X3-16+X+42
=>3x+x+42-16
=>4x+26
=>2 (x+13)