Factories) : x³+x²-10x+8
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Answer:
Step-by-step explanation:
Answer:
Given:
- polynomial x³+x²-10x+8
To factorise it
Pre-requisite Knowledge
Factor theorem : if 'a' is the root of the polynomial p(x) , then p(a) = 0
Solving question:
first we have to substitute values for 'x' in order to find whether it is a root.
substitute x = 1
Solution:
x = 1
x³+x²-10x+8
⇒ 1³ +1² -10*1 +8
⇒ 1+1 -10 +8
⇒-10 +10
⇒ 0
Hence, 1 is a root.
∴ (x-1) is a factor of the polynomial.
Divide it with this
After that we get quotient as x²+ 2x -8
Factorize: x²+ 2x -8
⇒ x² +4x -2x -8
⇒ x( x +4) -2(x + 4)
⇒ (x +4) (x-2) = 0
∴ The factors are (x-1) , (x+4) and (x -2)
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