Math, asked by yoyo4366, 10 months ago

Factories) : x³+x²-10x+8

Answers

Answered by sachingguu
5

10 will be it's answer will help you

Answered by KDPatak
16

Answer:

Step-by-step explanation:

Answer:

Given:

  • polynomial  x³+x²-10x+8

To  factorise it

Pre-requisite Knowledge

Factor theorem : if 'a' is the root of the polynomial p(x) , then p(a) = 0

Solving question:

 first we have to substitute values for 'x' in order to find whether it is a root.

substitute x = 1

Solution:

x = 1

x³+x²-10x+8

1³ +1² -10*1 +8

1+1 -10 +8

-10 +10

0

Hence, 1 is a root.

∴ (x-1) is a factor of the polynomial.

Divide it with this

After that we get quotient as x²+ 2x -8

Factorize: x²+ 2x -8

x² +4x -2x -8

x( x +4) -2(x + 4)

(x +4) (x-2) = 0

∴ The factors are (x-1) , (x+4) and (x -2)

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