Math, asked by goyalkaran123com, 2 months ago

factoring 64/27z^3-1-16/3z^2+4z​

Answers

Answered by ragini8499kumari
0

How to solve your problem

6

4

2

7

3

1

1

1

6

3

2

+

4

\frac{64}{27} \cdot z^{3}-1-1 \cdot \frac{16}{3} \cdot z^{2}+4z

2764⋅z3−1−1⋅316⋅z2+4z

Simplify

1

Combine multiplied terms into a single fraction

6

4

2

7

3

1

1

1

6

3

2

+

4

\frac{64}{27}z^{3}-1-1 \cdot \frac{16}{3} \cdot z^{2}+4z

2764z3−1−1⋅316⋅z2+4z

6

4

3

2

7

1

1

1

6

3

2

+

4

Similar questions