Question

factoring the sum or difference of two cubes x^3 - 729

Answer 1

Answer:

You have to observe that 729=93 , and so x3−729 is a difference of cubes. a3−b3=(a−b)(a2+ab+b2) , and (a2+ab+b2) is no longer factorizable (it is also known as "false square", because it resembles (a+b)2 , but the mixed product is halved).

Answer 2

Step-by-step explanation:

You have to observe that 729=93 , and so x3−729 is a difference of cubes. a3−b3=(a−b)(a2+ab+b2) , and (a2+ab+b2) is no longer factorizable (it is also known as "false square", because it resembles (a+b)2 , but the mixed product is halved).

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