factoring with all techiniques
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x⁷+2x⁴+x
= x⁷+x⁴+x⁴+x
=x⁴(x³+1)+x(x³+1)
=(x³+1)(x⁴+x)
1/x³(x⁷+2x⁴+x)
=x⁴+2x+1/x²
=(x²)²+2×x²×1/x+(1/x)²
=(x²+1/x)²
= x⁷+x⁴+x⁴+x
=x⁴(x³+1)+x(x³+1)
=(x³+1)(x⁴+x)
1/x³(x⁷+2x⁴+x)
=x⁴+2x+1/x²
=(x²)²+2×x²×1/x+(1/x)²
=(x²+1/x)²
saumik61:
in the second method to keep the value same we should multiply it by x³
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X³×1/x³(x⁷+2x⁴+x)
x³(x⁴+2x+1/x²)
x³(x²+1/x)²
x³(x⁴+2x+1/x²)
x³(x²+1/x)²
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