Physics, asked by wanted51, 1 year ago

Factoring with repeated of the difference of square formula. Factor the answer completely.

3y4 – 3u4y4.​

Answers

Answered by Anonymous
4

// Hell0 //

Explanation:

❤◽Solution:

3y4 – 3u4y4.

= 3y4(1 – u4).

= 3y4(1 – (u2)2).

= 3y4(1 + u2)( 1 - u2) [since we know a2 – b2 = (a + b)(a – b)].

= 3y4(1 + u2)( 1 + u) ( 1 - u).

Answer: 3y4(1 + u2)( 1 + u) ( 1 - u).

Hope it helps

#Hopēless_ Romañtic

Answered by Anonymous
1

Explanation:

3y4 – 3u4y4.

= 3y4(1 – u4).

= 3y4(1 – (u2)2).

= 3y4(1 + u2)( 1 - u2) [since we know a2 – b2 = (a + b)(a – b)].

= 3y4(1 + u2)( 1 + u) ( 1 - u).

Answer: 3y4(1 + u2)( 1 + u) ( 1 - u)..

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