Question

Factoring with repeated of the difference of square formula. Factor the answer completely.

u4x3 – 81x3.

Answer 1

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Solution

u4x3 – 81x3.

= x3(u4 – 81).

= x3((u2)2 – 92).

= x3(u2 + 9)(u2 – 9).

= x3(u2 + 9)(u2 – 32).

= x3(u2 + 9)(u + 3)(u – 3).

Answer - x3(u2 + 9)(u + 3)(u – 3).


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Answer 2

$u {}^{4} x {}^{3} - 81x {}^{3} \\ \\ = x {}^{3} (u {}^{4} - 81) \\ \\ = x {}^{3} ((u{}^{2}) {}^{2} - (3 {}^{2} ) {}^{2} ) \\ \\ = x {}^{3} (u {}^{2} + 9)(u {}^{2} - 9)$
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