Question

Factorisation
(1+a)^2(1+b)^2 - (1+a^2)(1+b^2)​

Answer 1

Answer:

(1+a)2(1+b2)−(1+b)2(1+a2)

=

[(1+a)2(1+b2)−−−−−−−−−−−−−√]2−[(1+b)2(1+a2)−−−−−−−−−−−−−√]2

=

[(1+a)2(1+b2)−−−−−−−−−−−−−√−[(1+b)2(1+a2)−−−−−−−−−−−−−√][(1+a)2(1+b2)−−−−−−−−−−−−−√+[(1+b)2(1+a2)−−−−−−−−−−−−−√]