Question

factorisation
25a2-4b2+28bc-49c2

Answer 1

Step-by-step explanation:

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Answer 2

25a2 – 4b2 + 28bc – 49c2

= (5a)2 – (4b2 – 28bc + 49c2)

= (5a)2 – {(2b)2 – 2(2b)(7c) + (7c)2}

    using formula  x2 – 2xy + y2 =(x – y)2  where x=2b ,y=7c

= (5a)2 – (2b – 7c)2 = (5a – 2b + 7c)(5a + 2b – 7c)            

  using formula x2 – y2  =  (x– y) (x + y)  where x=5a and y=2b-7c

Answer = (5a – 2b + 7c)(5a + 2b – 7c)