factorisation (2x+4)^2-1
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Answered by
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(2x+4)²-1
=[(2x)²+2(4)(2x)+(4)²]-1
=[4x²+16x+16]-1
=4x²+16x+16-1
=4x²+16x+15
Answered by
0
Answer:
(2x+5)(2x+3)
Step-by-step explanation:
(2x+4)^2-(1)^2
x^2-y^2=(x+y)(x-y)
(2x+4)^2-(1)^2=((2x+4)+1)((2x+4)-1)
=(2x+5)(2x+3)
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