factorisation 4x2-5x+1=0
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Answer:
4x2-5x+1=0
4x2-4x-x+1=0
4x(x-1)+x(x-1)=0
(4x-1)(x-1)=0
x=1/4 or x=1
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Hope it will be helpful to you
Step-by-step explanation:
Given ax2 + bx + c = 0, find two integers with b as the sum and ac as the product. With 4x2 - 5x + 1 = 0, for example, you want two integers with a sum of -5 and a product of 4*1 = 4. You can now factor by grouping: 4x2 - 5x + 1 = 4x2 - 4x - x + 1 = 4x(x - 1) - 1(x - 1) = (4x - 1)(x - 1)
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