Question

Factorisation
6a2 + 19a + 10
Solve:​

Answer 1

Solution:

${6a² + 19a + 10}$

= $\bold{6a²+15a+4a+10}$

= $\bold{3a(2a+5)+2a(2a+5)}$

= $\boxed{{(3a+2)(2a+5)}}$

Answer 2

Answer:

$6a^{2} + 19a + 10 \\ = 6a ^{2} + 15a + 4a + 10 \\ = 3a(2a + 5) + 2a(2a + 5) \\ = (3a + 2)(2a + 5)$