factorisation :- a-b-a²+b²
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re arranging the terms
a-a^2-b-b^2
a(1-a)-b (1-b)
a-a^2-b-b^2
a(1-a)-b (1-b)
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Answer:
Q- a-b-a²+b²
= a-b-a²+b²
=(a-b)-(a²-b²)
=(a-b)-(a-b)(a+b)
=(a-b) [1-(a+b)
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