Question

factorisation assignment solve fast please​

Answer 1

Answer:

do all bits as I did

thank you

Answer 2

Answer:

The answers for the factorisation assignments are as follows

Step-by-step explanation:

The following expression expression are the areas of rectangle.find the posssible lenghts and breadths of these rectangles

i)$x^{2} -6x+8$

$= x^{2} -6x+8\\= x^{2} -2x-4x+8$

the solutions we get are (x-2) and (x-4)

therefore , length=4 and breadth=2

           or length=2 and breadth=4

ii)$x^{2} -3x+2$

$=x^{2} -3x+2\\=x^{2} -x-2x+2$

the solutions we get are (x-2) and (x-1)

therefore , length=2 and breadth=1

           or length=1 and breadth=2

iii)$x^{2} -7x+10$

=x^{2} -7x+10

=x^{2} -2x-5x+10

the solutions we get are (x-5) and (x-2)

therefore , length=5 and breadth=12

           or length=2 and breadth=5

iv) $x^{2} +19x-20$

=x^{2} +19x-20

=x^{2} +20x-x-20

the solutions we get are (x-1) and (x+20)

therefore , length=1and breadth=-20

           or length=-20 and breadth=1

v) $x^{2} +9x+20$

= $x^{2} +9x+20\\x^{2} +5x+4x+20$

the solutions we get are (x+4) and (x+5)

therefore , length= -4and breadth= -5

           or length= -5 and breadth= -4