Question

Factorisation Grouping the terms 16(a+b)²-4a-4b​

Answer 1

Answer:

In △ABC,

∠A=∠B+∠C

Now, sum of angles = 180

∠A+∠B+∠C=180

∠A+∠A=180

∠A=90

∘

Thus, △ABC, is a right angled trian

Answer 2

To Factorise:

${\green{16(a+b)²–4a–4b}}$

$———————————————$

$16(a+b)²–4a–4b$

$= = > 16{(a + b) }^{2} - 4(a + b)$

$= = > 4(a + b)[4(a + b) - 1]$

$= = > {\blue{4(a + b)(4a + 4b - 1)}}$

$———————————————$

${\large{\mathcal{\red{Have \: a \: nice \: day \: ahead}}}}$