Question

factorisation ( introduction) find the H.C.F of : x²y³ , xy⁴ and x³y² . ​

Answer 1

Answer:

a=x3y2

b=xy3

For finding hcf(a,b)

a= x x x y y

b= x y y y

the terms same in both a and b are x y y

x y y = xy2

Hence, HCF(a,b)=xy2

Hope it helps you.

Answer 2

Answer:

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