Question

factorisation method 1/x-2+2/x+2=6/x​

Answer 1

Answer:

Given: 3x

2

−2

6

x+2=0

3x

2

−

6

x−

6

x+2=0,

3

x(

3

x−

2

)−

2

(

3

x−

2

)=0

(

3

x−

2

)(

3

x−

2

)=0∴

3

x−

2

=0 or

3

x−

2

=0

∴

3

x=

2

or

3

x=

2

,x=

3

2

or x=

3

2

So, the root is repeated twice, one for each repeated factor (

3

x−

2

)l.

∴ The two equal roots of 3x

2

−2

6

x+2=0 are

3

2

,

3

2

.

$\div$