Question

factorisation method 3xsquare -22x-16=0​

Answer 1

Step-by-step explanation:

3x²-22x-16=0

3x²-24x+2x-16=0

3x(x-8)+2(x-8)=0

(x-8)(3x+2)=0

(x-8)=0. Or. 3x+2=0

X=8 or x=-2/3

Answer 2

Answer:

x=8 or x= -2/3=9

Your question:- 3x²-22x-16=0

Solution:- First we will multiply the coefficients of the first and the last term

-16×3=-48

Now we will split the coefficient of the middle term in such a way that the product will be equal to 48.

We will split -22 as, -24+2

So the equation will be

3x²-24x+2x-16=0

Now we will take the common terms

3x(x-8)+2(x-8)=0

Here (x-8) is the common term.

(x-8)(3x+2)=0

This equation is possible if one the terms is equal to zero. So the value of x can be

x-8=0 or 3x+2=0

x=8 or x= -2/3

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