Question

factorisation method : a ( 3a - 2 ) -1

Answer 1

Hola!

your answer is ---

we have ,

$a(3a - 2) - 1 \\ = 3 {a}^{2} - 2a - 1 \\ = 3 {a}^{2} - 3a + a - 1 \\ = 3a(a - 1) + (a - 1) \\ = (a - 1)(3a + 1)$





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