Question

factorisation method
${x}^{2} = 2(11x - 48)$

Answer 1

$x^{2} = 2(11x - 48)$

$x^2 = 22x - 96$

$x^2 - 22x + 96 = 0$

Sum = -22, Product = 96 {Numbers are '-6' and '-16'}

$x^{2} - 16x - 6x + 96 = 0$

$x(x - 16) - 6(x-16) = 0$

$(x-6)(x-16) =0$

Hence, x = 6 and 16 

Answer 2

x²=2(11x-48)
x²=22x-96
x²-(22x-96)=0

x²-22x+96=0
x²-6x-16x+96=0
x(x-6)-16(x-6)=0
(x-16)(x-6)

x-16=0

x=16

and

x-6=0
x=6