Math, asked by sasank4540, 11 months ago

factorisation of 1+64x^2​

Answers

Answered by rinisen
0

Answer:

Step-by-step explanation:

: A difference of two perfect squares,  A2 - B2  can be factored into  (A+B) • (A-B)

Proof :  (A+B) • (A-B) =

        A2 - AB + BA - B2 =

        A2 - AB + AB - B2 =

        A2 - B2

Note :  AB = BA is the commutative property of multiplication.

Note :  - AB + AB equals zero and is therefore eliminated from the expression.

Check :  1  is the square of  1

Check : 64 is the square of 8

Check :  x2  is the square of  x1

Factorization is :       (1 + 8x)  •  (1 - 8x)

(8x + 1)  (1 - 8x)

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