Math, asked by ShemreingamMungrei, 8 months ago

factorisation of 2(a+b)2-8(a -b)2

Answers

Answered by vijayapravallikapatt
1

2(a+b)^2 - 8(a-b)^2

2[a^2 + b^2 + 2ab] - 8[a^2 + b^2 - 2ab]

2a^2 + 2b^2 + 4ab - 8a^2 - 8b^2 + 16ab

-6a^2 -6b^2 + 20ab

-6a^2 + 20ab -6b^2

-6a^2 + 2ab + 18ab -6b^2

2a[-3a+b] - 6b[-3a+b]

(2a - 6b) (-3a+b)

(2a - 6b) (b - 3a)

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