Question

Factorisation of 3√3x^3 - 8 is
(1) (√3x - 2) (3x^2 + 2√3x + 4)
(2 (√3x + 2) (3x^2 + 2√3x + 4)
(3) (√3x - 2) (3x^2 + 2√3x + 8)
(4) (√3x - 2) (3x^2 - 2√3x + 4)​

Answer 1

Answer:

Sorry I don't know

Step-by-step explanation:

As I am in 6th class