Math, asked by diveshnarahjaat12, 1 month ago

Factorisation of 3√3x^3 - 8 is
(1) (√3x - 2) (3x^2 + 2√3x + 4)
(2) (√3x + 2) (3x^2 + 2√3x + 4)
(3) (√3x - 2) (3x^2 + 2√3x + 8)
(4) (√3x - 2) (3x^2 - 2√3x + 4)​

Answers

Answered by itsnasreensahaikh
2

Step-by-step explanation:

(√3x - 2) (3x^2 + 2√3x + 4)

(2) (√3x + 2) (3x^2 + 2√3x + 4)

(3) (√3x - 2) (3x^2 + 2√3x + 8)

(4) (√3x - 2) (3x^2 - 2√3x + 4)

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