factorisation of 4(x+y)-6(x+y)^2
Answers
Answered by
96
Hi there !!
Here's your answer
Given,
To factorise
4(x + y) - 6(x + y)²
Taking out common factor as 2(x + y)
we have,
2(x + y)[ 2 - 3(x + y)
2(x + y)( 2 - 3x - 3y)
Or
(2x + 2y)(2 - 3x - 3y)
___________________
Hope it helps :D
Here's your answer
Given,
To factorise
4(x + y) - 6(x + y)²
Taking out common factor as 2(x + y)
we have,
2(x + y)[ 2 - 3(x + y)
2(x + y)( 2 - 3x - 3y)
Or
(2x + 2y)(2 - 3x - 3y)
___________________
Hope it helps :D
Anonymous:
:-)
Answered by
27
Step-by-step explanation:
2(x+y) [2-3(x+y)]
2(x+y) [2-3(x+y)]= 2(x+y) [2-3x-3y]
2(x+y) [2-3(x+y)]= 2(x+y) [2-3x-3y]=(2x+2y) (2-3x-3y)
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