Question

Factorisation of 4x^2 Y^3 + 2xy is with steps ​

Answer 1

Step-by-step explanation:

(1): "^-2" was replaced by "^(-2)".

(2): "y1" was replaced by "y^1".

STEP

1

:

y11

Simplify ———

x

Equation at the end of step

1

:

(y3) (y5) y11

(((((4•(x2))•————)•x)•y)-((15x•————)•(y3)))+((13x•(y-2))•———)

2 3 x

STEP

2

:

Equation at the end of step

2

:

(y3) (y5) y11

(((((4•(x2))•————)•x)•y)-((15x•————)•(y3)))+(13xy(-2)•———)

2 3 x

STEP

3

:

y5

Simplify ——

3

Equation at the end of step

3

:

(y3) y5

(((((4•(x2))•————)•x)•y)-((15x•——)•y3))+13y9

2 3

STEP

4

:

Multiplying exponential expressions :

4.1 y5 multiplied by y3 = y(5 + 3) = y8

Equation at the end of step

4

:

(y3)

(((((4•(x2))•————)•x)•y)-5xy8)+13y9

2

STEP

5

:

y3

Simplify ——

2

Equation at the end of step

5

:

y3

(((((4•(x2))•——)•x)•y)-5xy8)+13y9

2

STEP

6

:

Equation at the end of step

6

:

y3

((((22x2 • ——) • x) • y) - 5xy8) + 13y9

2

STEP

7

:

Dividing exponents:

7.1 22 divided by 21 = 2(2 - 1) = 21 = 2

Equation at the end of step

7

:

(((2x2y3 • x) • y) - 5xy8) + 13y9

STEP

8

:

STEP

9

:

Pulling out like terms

9.1 Pull out like factors :

2x3y4 - 5xy8 + 13y9 = y4 • (2x3 - 5xy4 + 13y5)

Trying to factor a multi variable polynomial :

9.2 Factoring 2x3 - 5xy4 + 13y5