Factorisation of 4x^2 Y^3 + 2xy is with steps
Answers
Step-by-step explanation:
(1): "^-2" was replaced by "^(-2)".
(2): "y1" was replaced by "y^1".
STEP
1
:
y11
Simplify ———
x
Equation at the end of step
1
:
(y3) (y5) y11
(((((4•(x2))•————)•x)•y)-((15x•————)•(y3)))+((13x•(y-2))•———)
2 3 x
STEP
2
:
Equation at the end of step
2
:
(y3) (y5) y11
(((((4•(x2))•————)•x)•y)-((15x•————)•(y3)))+(13xy(-2)•———)
2 3 x
STEP
3
:
y5
Simplify ——
3
Equation at the end of step
3
:
(y3) y5
(((((4•(x2))•————)•x)•y)-((15x•——)•y3))+13y9
2 3
STEP
4
:
Multiplying exponential expressions :
4.1 y5 multiplied by y3 = y(5 + 3) = y8
Equation at the end of step
4
:
(y3)
(((((4•(x2))•————)•x)•y)-5xy8)+13y9
2
STEP
5
:
y3
Simplify ——
2
Equation at the end of step
5
:
y3
(((((4•(x2))•——)•x)•y)-5xy8)+13y9
2
STEP
6
:
Equation at the end of step
6
:
y3
((((22x2 • ——) • x) • y) - 5xy8) + 13y9
2
STEP
7
:
Dividing exponents:
7.1 22 divided by 21 = 2(2 - 1) = 21 = 2
Equation at the end of step
7
:
(((2x2y3 • x) • y) - 5xy8) + 13y9
STEP
8
:
STEP
9
:
Pulling out like terms
9.1 Pull out like factors :
2x3y4 - 5xy8 + 13y9 = y4 • (2x3 - 5xy4 + 13y5)
Trying to factor a multi variable polynomial :
9.2 Factoring 2x3 - 5xy4 + 13y5