factorisation of 4x2+8x+3=0
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Answer:
x = -1/2 , -3/2
Step-by-step explanation:
4x2 +8x+3=0
4x2+6x+2x+3=0
2x(2x + 3) + 1 (2x + 3)
(2x+1) (2x+3)
x = -1/2 , -3/2 Answer.....
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Answered by
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Answer:
we have
4x2+8x+3=0
i.e.,
4x^2+8x+3=0 , so now we will break 8x means we will make factors of 8x in such a way that addition is 8x and multiplication is 12x^2 .
4x^2+6x+2x+3=0
now take 2x common from 4x^2+6x and
+1 from 2x+3 therefor
2x(2x+3)+1(2x+3)=0
now we have two different things
2x+3=0 and 2x+1=0
2x=(-3) and 2x=(-1)
x=(-3)/2 and x=(-1)/2
and we have two answers of x.
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