Math, asked by rajivkumar31200, 9 months ago

factorisation of 4x2+8x+3=0
full solved answer please
and don't answer if you don't know othervise your answer will be reported​

Answers

Answered by karanagg2005
0

Answer:

x = -1/2 , -3/2

Step-by-step explanation:

4x2 +8x+3=0

4x2+6x+2x+3=0

2x(2x + 3) + 1 (2x + 3)

(2x+1) (2x+3)

x = -1/2 , -3/2 Answer.....

Plzz mark it as brainliest. Its fully solved...... Step wise

Answered by ramanmoni
0

Answer:

we have

4x2+8x+3=0

i.e.,

4x^2+8x+3=0 , so now we will break 8x means we will make factors of 8x in such a way that addition is 8x and multiplication is 12x^2 .

4x^2+6x+2x+3=0

now take 2x common from 4x^2+6x and

+1 from 2x+3 therefor

2x(2x+3)+1(2x+3)=0

now we have two different things

2x+3=0 and 2x+1=0

2x=(-3) and 2x=(-1)

x=(-3)/2 and x=(-1)/2

and we have two answers of x.

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