Question

Factorisation of 5x2-26x+28

Answer 1

Answer:

$\frac{1}{5} (5x-13-\sqrt{29} )(5x-13+\sqrt{29} )$

Step-by-step explanation:

Factoring $5x^2-26x+28$ in Real Number

Find the zeroes of $5x^2-26x+28$.

∴$x=\frac{13+\sqrt{29} }{5}$ or $x=\frac{13-\sqrt{29} }{5}$

Use the zeroes to factor.

( When the zeroes of a quadratic equation $ax^2+bx+c=0$ are $\alpha$ and $\beta$ )

$a(x-\alpha )(x-\beta )=0$

∴$5(x-\frac{13+\sqrt{29} }{5})(x-\frac{13-\sqrt{29} }{5})$

Or we can make it simpler.

∴$\frac{1}{5} (5x-13-\sqrt{29} )(5x-13+\sqrt{29} )$