Question

factorisation of 63a^2-112b^2

Answer 1

Answer:

First of all there is no square root of 63 and 112 so, we must take the common numbers..

i.e. ( 3 * 3 * 7 * a * a ) - ( 2 * 2 * 2 * 2 * 7 * b * b )

Taking the common factors we'll get 7 ( 9 a^2 - 16 b^2 )

= 7 ( 3a^2 - 4b^2 )

And your final answer will be 7 ( 3a - 4b ) ( 3a + 4b )

Hope it helped...

Step-by-step explanation:

Answer 2

Answer:

7(3a+4b)(3a−4b) Brainliest Please

Step-by-step explanation:

63a 2 −112b 2

=7(9a^2 −16b^2 )

=7[(3a)^2 −(4b)^2 ]

Using, a^2 −b^2 =(a+b)(a−b)

=7(3a+4b)(3a−4b)