factorisation of 64a³b³ ─ 27 is: *
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Step-by-step explanation:
64a³b³ ─ 27
= (4ab)^3 - (3)^3
=. (4ab-3) ( 16a^2b^2 - 12ab + 9)
By using identity a^3 - b^3 = (a- b) ( a^2- ab+ b^2)
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