Question

factorisation of h^3-3h^2+4​

Answer 1

Answer:

If we substitute h= -1 then polynomial

${h}^{3} - 3 {h}^{2} + 4$

It is equal to 0. Hence (h+1) is a zero of the above polynomial. So if we divide the polynomial by (h+1) ,

we get

${h}^{2} - 4h + 4$

as quotient and

we can express

$h^{2} - 4h + 4 \: as {(h - 2)}^{2}$

Hence the factorisation of

${h}^{3} - 3 {h}^{2} + 4 \:$

is

$(h + 1) \times {(h - 2)}^{2}$

Hope it helps you.