factorisation of p squre + p - 6
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Answered by
1
Step-by-step explanation:
p²-p-6
p²-3p+2p-6
p(p-3)+2(p-3)
(p+2)(p-3)
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Answered by
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P^2+P-6=0
P^2+3p-2p-6=0
P(P+3)-2(P+3)=0
(P+3)(P-2)=0
P=-3 or 2
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