Question

factorisation of the expression z⁶-7z³-8 ​

Answer 1

Answer:

(z+1)(z^2-z+1)(z-2)(z^2+2z+4)

the given question can be factorized

to (z^3+1)(z^3-8)

and on applying a^3+b^3 and a^3-b^3

we get

(z+1)(z^2-z+1)(z-2)(z^2+2z+4)

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